5x+20=x^2+4x

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Solution for 5x+20=x^2+4x equation:


Simplifying
5x + 20 = x2 + 4x

Reorder the terms:
20 + 5x = x2 + 4x

Reorder the terms:
20 + 5x = 4x + x2

Solving
20 + 5x = 4x + x2

Solving for variable 'x'.

Combine like terms: 5x + -4x = 1x
20 + 1x + -1x2 = 4x + x2 + -4x + -1x2

Reorder the terms:
20 + 1x + -1x2 = 4x + -4x + x2 + -1x2

Combine like terms: 4x + -4x = 0
20 + 1x + -1x2 = 0 + x2 + -1x2
20 + 1x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
20 + 1x + -1x2 = 0

Factor a trinomial.
(5 + -1x)(4 + x) = 0

Subproblem 1

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {5, -4}

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